ETL 1110-9-10(FR)

5 Jan 91

A = AT + AC + AB

(eq 2-1)

Where:

AT = Wetted area of the top section

AC = Area of the center section

AB = Area of the bottom section.

a)

Find the appropriate wetted area of the top

section (AT) using equation 2-2:

AT = 2 B rh

(eq 2-2)

Where:

r

=

28 ft (Tank radius)

h

=

10 ft (Water height)

AT =

2 x 3.1416 x 28 ft x 10 ft

A

=

1759 sq ft (approximate).

b)

Find the wetted area of the center section (AC)

using equation 2-2:

AC = 2 B rh

(eq 2-2)

r

=

28 ft (Tank radius

h

=

11 ft (Water height)

AC =

2 x 3.1416 x 28 ft x 11 ft

A

=

1935 sq ft

c)

Find the wetted area of the bottom section (AB)

from equation 2-3:

AB '

2 A r h2 % r2

(eq 2-3)

Where:

r = 28 ft (Tank radius)

h = 14 ft (Water height)

AB ' 2 3.1416 28 (14)2 % (28)2

AB = 3894 sq ft

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