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ETL 1110-9-10(FR)
5 Jan 91
A = AT + AC + AB
(eq 2-1)
Where:
AT = Wetted area of the top section
AC = Area of the center section
AB = Area of the bottom section.
a)
Find the appropriate wetted area of the top
section (AT) using equation 2-2:
AT = 2 B rh
(eq 2-2)
Where:
r
=
28 ft (Tank radius)
h
=
10 ft (Water height)
AT =
2 x 3.1416 x 28 ft x 10 ft
A
=
1759 sq ft (approximate).
b)
Find the wetted area of the center section (AC)
using equation 2-2:
AC = 2 B rh
(eq 2-2)
r
=
28 ft (Tank radius
h
=
11 ft (Water height)
AC =
2 x 3.1416 x 28 ft x 11 ft
A
=
1935 sq ft
c)
Find the wetted area of the bottom section (AB)
from equation 2-3:
AB '
2 A r h2 % r2
(eq 2-3)
Where:
r = 28 ft (Tank radius)
h = 14 ft (Water height)
AB ' 2 3.1416 28 (14)2 % (28)2
AB = 3894 sq ft
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